AQA 3.1.11.1 · OCR A 5.2.3 · Year 13
Electrode potentials and electrochemical cells
Start by pinning each E° value to its redox couple, then build the physical cell and practise the reasoning and wording that AQA and OCR A expect.
Choose a route
Get the chemistry straight, then make it exam-safe
Start with the convention
Every tabulated E° half-equation is written as a reduction
For E°(Zn2+/Zn) = −0.76 V, the table is referring to the reduction half-equation Zn2+ + 2e− ⇌ Zn. In an actual cell, zinc metal may run in the opposite direction and be oxidised.
The more positive E° couple has the greater tendency to run in the reduction direction. Reverse the other half-equation for the cell reaction. E° stays unchanged when you scale a half-equation to balance electrons.
Exam precision
Name the couple, then name the reacting species
When I check an electrode-potential explanation, I want to see the redox couple and the reacting species named. That keeps the direction of oxidation and reduction clear on either board.
“Zinc has a lower electrode potential, so it reacts.”
E°(Zn2+/Zn) is more negative than E°(V3+/V2+), so Zn is oxidised and V3+ is reduced to V2+.
Away from standard conditions
E° applies to standard conditions
If concentration or gas pressure changes, treat the half-equation as an equilibrium. A shift towards reduction makes the actual electrode potential more positive; a shift towards oxidation makes E less positive.
The tabulated E° value stays fixed. At A-level you can reason this out without using the Nernst equation.
Try the E versus E° lab →Common mistakes to avoid
From half-cells to real devices
Build the physical cell for the practical side, or carry the same redox reasoning into storage cells, recharging and fuel cells. The commercial-cell route changes what it expects you to recall depending on AQA or OCR A.