Module 4: Core Organic Chemistry · Year 12

4.2.4 Analytical techniques

Use IR and mass spectra as evidence: identify characteristic bonds, read molecular mass and fragments, then make one structure that fits all the data.

What you need to know

Open a line for a quick recap. If it feels obvious, move straight to the linked practice.

4.2.4 a Explain that IR radiation makes covalent bonds vibrate more and absorb energy. Quick revision

Covalent bonds are not rigid sticks: they vibrate. When a molecule absorbs infrared radiation of the right frequency, the vibration of a bond can increase in energy.

Different bonds and molecular environments absorb at different wavenumbers, which is why an IR spectrum can give you evidence about which bonds and functional groups are present.

4.2.4 b Explain how infrared-active bond vibrations in molecules containing C=O, O–H or C–H can absorb IR radiation, and connect this to evidence about greenhouse warming. Quick revision

When you think about IR absorption, remember that suitable bond vibrations can take up particular frequencies of infrared radiation. Molecules containing bonds such as C=O, O–H and C–H can therefore absorb IR and gain vibrational energy.

That matters for greenhouse warming because Earth emits infrared radiation. Greenhouse gases absorb some of that outgoing IR and can re-emit energy in different directions, reducing the rate at which energy escapes to space. Keep the explanation about IR absorption and re-emission; do not say the gas simply “traps heat” with no mechanism.

4.2.4 c Use an IR spectrum to identify alcohols, aldehydes/ketones and carboxylic acids from O-H and C=O absorptions. Quick revision

When you identify these familiar functional groups from IR, look for combinations of the broad O–H region and the strong C=O absorption. An alcohol has an O–H absorption but no carbonyl; an aldehyde or ketone has C=O without the broad acid O–H; a carboxylic acid has both C=O and a very broad O–H absorption.

Use the OCR Data Sheet for the exact ranges in an exam. The shape matters too: the carboxylic-acid O–H absorption is broader and extends lower than the alcohol O–H region.

  • alcohol: O–H present, C=O absent
  • aldehyde/ketone: C=O present, acid O–H absent
  • carboxylic acid: C=O + very broad O–H
Watch forDo not confuse the broad carboxylic-acid O–H absorption with the alcohol O–H region.
4.2.4 d Use supplied absorption ranges to identify features in IR spectra of both familiar and unfamiliar compounds. Quick revision

You do not need to rely on memorised wavenumber ranges when the question supplies the OCR data. Match a significant absorption to the range, then ask whether that bond makes sense in the proposed structure.

Treat IR as evidence, not as a one-peak naming machine. A strong C=O absorption narrows the possibilities; the presence or absence of O–H and other supplied regions helps you decide which functional group fits.

4.2.4 e Describe uses of IR spectroscopy for monitoring air pollutants and breath ethanol. Quick revision

IR can identify and measure substances because particular bonds absorb at characteristic wavenumbers. In air monitoring, an instrument can look for absorptions associated with pollutant molecules; in breath analysis, IR absorption can be used to estimate ethanol concentration.

The useful idea is selectivity: you choose wavelengths where the substance of interest absorbs and relate the amount of absorption to how much is present.

4.2.4 f Use the molecular ion peak in a mass spectrum to determine molecular mass. Quick revision

When you read an organic mass spectrum, the molecular ion represents the whole molecule after it has lost one electron. For the usual singly charged molecular ion, its m/z value gives the relative molecular mass, Mᵣ.

Look for the molecular-ion peak at the appropriate high-m/z end of the spectrum, but do not automatically assume the tallest peak is the molecular ion. The tallest peak is simply the base peak.

Watch forThe base peak is the most intense peak; it is not necessarily the molecular ion peak.
4.2.4 g Analyse fragmentation peaks in a mass spectrum and suggest structures of fragment ions. Quick revision

When the molecular ion breaks apart, some fragments keep the positive charge and appear as peaks. Use the m/z value to suggest a plausible charged fragment whose relative mass matches the peak.

I find it useful to work both ways: calculate the mass of a fragment you can see in the structure, or subtract a neutral loss from Mᵣ and ask what charged piece remains. Keep the charge on the fragment you are assigning to the peak.

Worked example

A peak at m/z 43 is common in spectra containing a suitable three-carbon fragment.

  1. 3 C = 36
  2. 7 H = 7
  3. 36 + 7 = 43

Answer C₃H₇⁺ is one possible fragment ion at m/z 43.

4.2.4 h Deduce structures of organic compounds using combined elemental analysis, mass spectra and IR spectra. Quick revision

For a structure problem, let each technique do the job it is good at. Elemental analysis can give an empirical formula; the molecular ion can give Mᵣ and hence the molecular formula; fragmentation suggests pieces of the carbon skeleton; IR tells you about bonds and functional groups.

Then make one structure that satisfies all the evidence. Before you finish, go back through the clues and check them against the structure you have drawn. If one fragment or IR absorption cannot come from your final molecule, the structure is not finished yet.

Watch forDo not choose a structure from one attractive clue and ignore the rest. Your final answer must account for every important piece of evidence.