3.3 Advanced Organic Chemistry · Year 13

3.3.10 Aromatic Chemistry

Use benzene delocalisation and electrophilic substitution to explain aromatic structure and reactions.

What you need to know

Open a line for a quick recap. If it feels obvious, move straight to the linked practice.

3.3.10.1 Describe benzene as planar with delocalised π electrons and carbon-carbon bond lengths between typical single and double bonds. Quick revision

Benzene has six π electrons delocalised over the ring, with six equivalent C–C bonds. The equal bond lengths and greater stability than a localised cyclohexatriene model support delocalisation.

When you draw or describe the model, keep the geometry and electron model together: each carbon is trigonal planar, each contributes a p orbital, and the continuous overlap gives a π system above and below the ring.

3.3.10.1 Explain benzene's extra stability by delocalisation relative to a hypothetical cyclohexa-1,3,5-triene structure. Quick revision

A localised cyclohexa-1,3,5-triene model would contain three ordinary C=C bonds. Real benzene is lower in energy because six π electrons are delocalised over the whole ring.

Use two observations as the clean evidence pair: all six C–C bonds have the same intermediate length, and hydrogenation is less exothermic than the three-isolated-C=C model predicts. Both point to one delocalised structure.

3.3.10.1 Use enthalpy-of-hydrogenation data as thermochemical evidence for benzene's stabilisation. Quick revision

Compare the measured enthalpy of hydrogenation with the value expected for three isolated C=C bonds. Benzene is less exothermic to hydrogenate than that model predicts, showing extra delocalisation stability.

Take the question’s hydrogenation value for one ordinary C=C bond and multiply it by three to build the localised model. The measured benzene value is less negative; that energy gap is the thermochemical evidence for extra stabilisation.

Worked example

A hypothetical ring with three isolated C=C bonds would be expected to hydrogenate by about −360 kJ mol⁻¹, but benzene hydrogenates by about −208 kJ mol⁻¹.

  1. benzene hydrogenation is 152 kJ mol⁻¹ less exothermic than the localised model
  2. the lower energy release means benzene started at a lower, more stable energy

Answer The data support substantial delocalisation stabilisation in benzene.

Watch forThe measured hydrogenation of benzene is less exothermic than the value expected for three isolated C=C bonds; that difference supports extra delocalisation stability.
3.3.10.1 Explain why benzene usually undergoes substitution rather than addition, preserving the delocalised ring system. Quick revision

Compare benzene with an alkene: addition would leave benzene without its stabilised delocalised π system. In electrophilic substitution the ring can restore that delocalisation when H⁺ is lost, so the aromatic system survives in the product.

That restoration of aromatic delocalisation is the key energetic reason benzene commonly substitutes where an alkene would add.

Watch forBenzene substitution restores the delocalised ring; an addition product would lose that aromatic stabilisation.
3.3.10.2 Recognise electrophilic aromatic substitution at benzene, with the required treatment limited to monosubstitution. Quick revision

For electrophilic substitution at benzene, let the ring regain its delocalised π system at the end. The π electrons attack the electrophile, a cationic intermediate forms, then loss of H⁺ restores the aromatic ring.

Once the ring has lost H⁺ and regained delocalisation, stop at the monosubstituted product for the treatment required here. The mechanism should finish with the aromatic ring restored.

3.3.10.2 Explain why nitration is useful in synthesis, including routes toward explosives and aromatic amines. Quick revision

For nitration, I’d remember why the NO₂ group is useful as well as the reaction itself. Nitro compounds are useful intermediates, and reducing –NO₂ gives an aromatic amine such as phenylamine.

A useful sequence to know is benzene → nitrobenzene → phenylamine, with the second step being reduction. Here the nitro group is an intermediate that opens a route to a different functional group.

C₆H₅NO₂ + 6[H] → C₆H₅NH₂ + 2H₂O
3.3.10.2 Recognise Friedel-Crafts acylation as a carbon-carbon bond-forming step in aromatic synthesis. Quick revision

Friedel–Crafts acylation forms a C–C bond by electrophilic substitution using an acylating reagent with AlCl₃. The aromatic ring is restored after substitution, giving an aryl ketone.

If you are planning a synthesis, the useful feature is the new C–C bond between the ring and the acyl group. That lets Friedel–Crafts acylation extend the carbon skeleton while retaining the aromatic ring.

C₆H₆ + CH₃COCl → C₆H₅COCH₃ + HCl
3.3.10.2 Draw electrophilic-substitution mechanisms for nitration (including NO₂⁺ generation) and AlCl₃-catalysed acylation. Quick revision

For nitration, you first generate NO₂⁺ from concentrated HNO₃ and H₂SO₄, then show benzene attacking the electrophile and losing H⁺ to restore delocalisation. For Friedel–Crafts acylation, AlCl₃ helps generate the acyl electrophile.

In both mechanisms, the ring attack forms a cationic intermediate and the final deprotonation restores the aromatic π system. Make that restoration visible; stopping at the cationic intermediate leaves the mechanism incomplete.

HNO₃ + H₂SO₄ → NO₂⁺ + HSO₄⁻ + H₂O
C₆H₆ + HNO₃ → C₆H₅NO₂ + H₂O
C₆H₆ + CH₃COCl → C₆H₅COCH₃ + HCl
Watch forFor nitration, the electrophile is NO₂⁺ and the mechanism must show restoration of the delocalised ring.